Mathematics Class Eight   Class 8 Subject List

Solutions of NCERT Exercise

Number System
Exercise 1
Exercise 2
Linear Equations
Problem&Solution:Type1
Exercise 1
Exercise 2
   Part 1     Part 2     Part 3
Exercise 3
   Part 1     Part 2
Exercise 4
   Part 1     Part 2
Exercise 5
   Part 1     Part 2
Exercise 6
   Part 1     Part 2
Quadrilaterals
Exercise 1
Exercise 2
Exercise 3
Exercise 4
Data Handling
Exercise 1
Exercise 2
Probability
Square & Square Roots
Exercise 1
Exercise 2
Exercise 3
   Part 1     Part 2
Exercise 4
Cube & Cube Roots
Exercise 1
Exercise 2
Comparing Quantities
Exercise 1
Exercise 2
Exercise 3
Algebraic Expressions
Exercise 1
Exercise 2 & 3
Exercise 4
Exercise 5
Exponents & Power
Factorization
Exercise 1
Exercise 2
Exercise 3
Mensuration
Mensuration:Problem:Type I
Mensuration:Problem:Type II
Exercise 1
Exercise 2
Exercise 3
Exercise 4
Proportion
Exercise 1
Exercise 2
Introduction to Graphs
Exercise 1
Exercise 2 & 3
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Linear Equations in One Variable

Exercise 2.2 (NCERT) Part - 1

Question – 1 – If you subtractSolution of exercise 2.2 Linear equations in one variable class eight math from a number and multiply the result by Solution of exercise 2.2 Linear equations in one variable class eight math1 , you get Solution of exercise 2.2 Linear equations in one variable class eight math2 . What is the number?

Solution:

Let the number is m.

Solution of exercise 2.2 Linear equations in one variable class eight math3

Question -2 - The perimeter of a rectangular swimming pool is 154 m. Its length is 2 m more than twice its breadth. What are the length and the breadth of the pool?

Solution:

Given, perimeter of the rectangular swimming pool = 154 m

Length is 2 m more than the breadth.

Let the breadth of the swimming pool = a metre

Therefore, as per question, length of the swimming pool = (2a + 2) metre

We know that, perimeter of rectangle = 2 (length + breadth)

Therefore, 154 m = 2 [ (2a + 2) + a]

⇒ 154 m = 2(2a + 2 + a )

⇒ 154 m = 2 (3a + 2)

⇒ 154 m = 6a + 4

By subtracting 4 from both sides, we get

154 m – 4 = 6a + 4 – 4

⇒ 150 m = 6a

After dividing both sides by 6, we get

Solution of exercise 2.2 Linear equations in one variable class eight math4

⇒ 25 m = a

⇒ a = 25 m

Since, length = (2a + 2) m

Therefore, by substituting the value of breadth (a), we get

(2 x 25 + 2) m= (50 + 2) m = 52 m

Thus, length of the given pool = 52 m

And breadth = 25 m

Question – 3 - The base of an isosceles triangle is Solution of exercise 2.2 Linear equations in one variable class eight math5 The perimeter of the triangle isSolution of exercise 2.2 Linear equations in one variable class eight math6 .What is the length of either of the remaining equal sides?

Solution:

Solution of exercise 2.2 Linear equations in one variable class eight math7
Solution of exercise 2.2 Linear equations in one variable class eight math8

Isosceles triangles have two sides equal.

We know that perimeter of an isosceles triangle = Sum of two equal sides + third side

Let the length of equal sides of the given isosceles triangle = a

And length of unequal side = b

Therefore, perimeter = 2a + b

Solution of exercise 2.2 Linear equations in one variable class eight math9

After dividing both sides by 2, we get

Solution of exercise 2.2 Linear equations in one variable class eight math10

Question – 4 - Sum of two numbers is 95. If one exceeds the other by 15, find the numbers.

Solution:

Let one number is ‘a’.

Therefore, according to question second number = a + 15

Now, as given, sum of two numbers = 95

Therefore,

a + a + 15 = 95

⇒ 2a + 15 = 95

By subtracting 15 from both sides, we get

2a + 15 – 15 = 95 – 15

⇒ 2a = 95 – 15

⇒ 2a = 80

After dividing both sides by 2, we get

Solution of exercise 2.2 Linear equations in one variable class eight math11

Now, since second number = a + 15

Therefore, by substituting the value of ‘a’, we get

The second number = 40 + 15 = 55

Thus, first number = 40 and second number = 55

Question: 5 - Two numbers are in the ratio 5:3. If they differ by 18, what are the numbers?

Solution:

Given, two numbers are in the ratio of 5:3

Their difference = 18

Solution of exercise 2.2 Linear equations in one variable class eight math12

After dividing both sides by 2, we get

Solution of exercise 2.2 Linear equations in one variable class eight math13
NEXT
Linear Equations in One Variable - Exercise - 2.2 - Part - 2
Linear Equations in One Variable - Exercise - 2.2 - Part - 3
   
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