Class 9 Science


Electronic Configuration

From Nitrogen (N) to Magnesium (Mg)

Electronic configuration of Nitrogen

Atomic number of nitrogen = 7.

Therefore number of electrons = 7

Thus, electronic configuration of nitrogen is electronic configuration of nitrogen

diagram of electronic configuration of nitrogen

Number of orbit in nitrogen = 2

Electronic configuration of Oxygen

Atomic number of oxygen = 8.

Therefore number of electrons = 8.

Thus, electronic configuration of oxygen is electronic configuration of oxygen

diagram of electronic configuration of oxygen

Number of orbit in oxgyen = 2

Electronic configuration of Fluorine

Atomic number of fluorine = 9

Therefore number of electrons = 9

Thus, electronic configuration of fluorine is electronic configuration of fluorine

diagram of electronic configuration of fluorine

Number of orbit in fluorine = 2

Electronic configuration of Neon

Atomic number of neon = 10

Therefore number of electrons = 10

Thus, electronic configuration of neon is electronic configuration of neon

diagram of electronic configuration of neon

Number of orbit in Neon = 2

Electronic configuration of Sodium

Atomic number of sodium = 11

Therefore number of electrons = 11

Since, in 2nd orbit the maximum number of electrons is equal to 8 and there are 11 electrons in sodium atom, thus the eleventh electron will go in third orbit.

Thus, electronic configuration of sodium is electronic configuration of sodium

diagram of electronic configuration of sodium

Number of orbit in sodium = 3

Electronic configuration of Magnesium

Atomic number of magnesium = 12

Therefore number of electrons = 12

Thus, electronic configuration of magnesium is electronic configuration of magnesium

diagram of electronic configuration of magnesium

Number of orbit in magnesium = 3.