NCERT Solution Part 2
Question 9: The basic unit of speed is:
Answer: (iv) m/s
Question 10: A car moves with a speed of 40 km/h for 15 minutes and then with a speed of 60 km/h for the next 15 minutes. The total distance covered by the car is:
- 100 km
- 25 km
- 15 km
- 10 km
Answer: Given, Speed for first 15 minute = 40km/h
Speed for next 15 minute = 60 km/h
We know that, Distance = Speed × Time
Therefore, Distance covered in first 15 minute i.e. 0.25 hour = 40 km/h × 0.24 hour = 10 km
Distance covered in next 15 minute = 60 km/h × 0.25 hour = 15 km
15 minute = ¼ hour = 0.25 hour
Thus, total distance covered = 10 km + 15 km = 25 km
Hence, Answer (ii) is correct
Question 11: Suppose the two photographs, shown in Fig. 13.1 and Fig. 13.2 (NCERT Book) had been taken at an interval of 10 seconds. If a distance of 100 metres is shown by 1 cm in these photographs, calculate the speed of the blue car.
Answer: Do the following steps to calculate the speed:
- Measure the distance cover by blue car.
- Multiply the distance measured in cm by 100 to get the distance covered by car in meter.
- Divide the distance in meter by 10 second (time given in question).
- Result will be the speed of car in meter/second.
Suppose the distance of car is 3.5 cm.
Thus, Distance covered by car = 3.5 × 100 = 350 meter.
Time (given in question) = 10 second
Speed = Distance ÷ Time
= 350 m ÷ 10 sec = 35 m per second
Question 12: Figure given here shows the distance-time graph for the motion of two vehicles A and B. Which one of them is moving faster?
Answer: Vehicle A is moving faster which is evident from higher slope for distance time graph of this vehicle, compared to that of the other vehicle.
Question 13: Which of the following distance-time graphs shows a truck moving with speed which is not constant?
Answer: (iii) The slope of the graph in this option is not a straight line and hence it does not show a uniform motion.